LEFTWARDS TWO HEADED ARROW·U+219E

Character Information

Code Point
U+219E
HEX
219E
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 86 9E
11100010 10000110 10011110
UTF16 (big Endian)
21 9E
00100001 10011110
UTF16 (little Endian)
9E 21
10011110 00100001
UTF32 (big Endian)
00 00 21 9E
00000000 00000000 00100001 10011110
UTF32 (little Endian)
9E 21 00 00
10011110 00100001 00000000 00000000
HTML Entity
↞
URI Encoded
%E2%86%9E

Description

The Unicode character U+219E, also known as the Leftwards Two-Headed Arrow, is a symbol with a unique role in digital text. Its primary function is to represent a bidirectional flow or transformation from one point to another. Typically used in mathematical equations and scientific notations, this character serves as an indicator of reversible processes or reactions. In programming and engineering contexts, it's also employed to illustrate data flows in reverse order or to denote the inverse of operations. It is particularly useful in fields such as physics, chemistry, engineering, and computer science where bidirectional transformations are commonplace. There is no significant cultural, linguistic, or technical context for this character beyond its functional use within these specific disciplines.

How to type the symbol on Windows

Hold Alt and type 8606 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+219E. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+219E to binary: 00100001 10011110. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10000110 10011110