BOPOMOFO LETTER NN·U+312F

Character Information

Code Point
U+312F
HEX
312F
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E3 84 AF
11100011 10000100 10101111
UTF16 (big Endian)
31 2F
00110001 00101111
UTF16 (little Endian)
2F 31
00101111 00110001
UTF32 (big Endian)
00 00 31 2F
00000000 00000000 00110001 00101111
UTF32 (little Endian)
2F 31 00 00
00101111 00110001 00000000 00000000
HTML Entity
ㄯ
URI Encoded
%E3%84%AF

Description

The Unicode character U+312F is a Bopomofo Letter NN, primarily used for representing the "nn" sound found in the Mandarin dialect of Chinese. In digital text, it serves as an essential element for accurately transcribing pinyin, which is the standard romanization system for the pronunciation of Mandarin. This character holds a crucial role in the fields of linguistics, language learning, and translation, particularly when working with Mandarin or other similar languages that utilize the Bopomofo system. The Bopomofo script, from which U+312F originates, was developed during the early 20th century to facilitate pronunciation and language teaching in Chinese education systems. As an integral part of this system, U+312F contributes to the accurate representation of Mandarin phonetics in digital texts worldwide.

How to type the symbol on Windows

Hold Alt and type 12591 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+312F. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+312F to binary: 00110001 00101111. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100011 10000100 10101111