BRAILLE PATTERN DOTS-2456·U+283A

Character Information

Code Point
U+283A
HEX
283A
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 A0 BA
11100010 10100000 10111010
UTF16 (big Endian)
28 3A
00101000 00111010
UTF16 (little Endian)
3A 28
00111010 00101000
UTF32 (big Endian)
00 00 28 3A
00000000 00000000 00101000 00111010
UTF32 (little Endian)
3A 28 00 00
00111010 00101000 00000000 00000000
HTML Entity
⠺
URI Encoded
%E2%A0%BA

Description

The Unicode character U+283A, known as BRAILLE PATTERN DOTS-2456, is a key element in digital text for the visually impaired. This Braille pattern represents the numerical digit "6" in the Braille alphabet system. Developed by Louis Braille in the early 19th century, this tactile writing system has revolutionized communication for individuals with visual disabilities by translating printed characters into a series of raised dots. In digital text format, U+283A allows visually impaired users to access information through braille displays and refreshable braille devices, enabling greater independence and participation in various aspects of life. As part of the Braille Dot Patterns Unicode block, U+283A contributes to the accessibility of written content for a diverse range of users worldwide.

How to type the symbol on Windows

Hold Alt and type 10298 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+283A. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+283A to binary: 00101000 00111010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10100000 10111010