IDEOGRAPHIC TELEGRAPH SYMBOL FOR DAY EIGHTEEN·U+33F1

Character Information

Code Point
U+33F1
HEX
33F1
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E3 8F B1
11100011 10001111 10110001
UTF16 (big Endian)
33 F1
00110011 11110001
UTF16 (little Endian)
F1 33
11110001 00110011
UTF32 (big Endian)
00 00 33 F1
00000000 00000000 00110011 11110001
UTF32 (little Endian)
F1 33 00 00
11110001 00110011 00000000 00000000
HTML Entity
㏱
URI Encoded
%E3%8F%B1

Description

The Unicode character U+33F1 represents the "IDEOGRAPHIC TELEGRAPH SYMBOL FOR DAY EIGHTEEN". This symbol has a significant role in digital text, particularly in Chinese telegraphy, where it was widely used to represent specific days within a month. The use of this character dates back centuries and has been essential in the field of information transmission and communication, especially in the context of China's long-standing telegraph history. It is important to note that this symbol does not follow any standard typographical rules, as it was developed for the specific purpose of telegraphy where brevity and efficiency were paramount. This character is still recognized today in Chinese culture, serving as a unique connection to the past in digital communication.

How to type the symbol on Windows

Hold Alt and type 13297 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+33F1. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+33F1 to binary: 00110011 11110001. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100011 10001111 10110001