CJK RADICAL C-SIMPLIFIED GATE·U+2ED4

Character Information

Code Point
U+2ED4
HEX
2ED4
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 BB 94
11100010 10111011 10010100
UTF16 (big Endian)
2E D4
00101110 11010100
UTF16 (little Endian)
D4 2E
11010100 00101110
UTF32 (big Endian)
00 00 2E D4
00000000 00000000 00101110 11010100
UTF32 (little Endian)
D4 2E 00 00
11010100 00101110 00000000 00000000
HTML Entity
⻔
URI Encoded
%E2%BB%94

Description

U+2ED4 is a character from the CJK Unified Ideographs Extension B block of the Unicode Standard. Specifically, it represents the CJK Radical "C-Simplified Gate" in digital text. This radical, originating from the ancient Chinese script, was historically used as a component in complex characters and served a structural role in forming those characters. In modern typography, U+2ED4 is utilized for educational purposes and to provide insight into the etymological composition of Chinese characters. However, it is not commonly employed in everyday text due to its complexity and limited usage in contemporary Chinese language. The character represents a simplified gate or door, typically associated with concepts of passage, transition, and entry.

How to type the symbol on Windows

Hold Alt and type 11988 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2ED4. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2ED4 to binary: 00101110 11010100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10111011 10010100