CJK STROKE HP·U+31C7

Character Information

Code Point
U+31C7
HEX
31C7
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E3 87 87
11100011 10000111 10000111
UTF16 (big Endian)
31 C7
00110001 11000111
UTF16 (little Endian)
C7 31
11000111 00110001
UTF32 (big Endian)
00 00 31 C7
00000000 00000000 00110001 11000111
UTF32 (little Endian)
C7 31 00 00
11000111 00110001 00000000 00000000
HTML Entity
㇇
URI Encoded
%E3%87%87

Description

U+31C7, the CJK Stroke HP character, is a specialized typographical element primarily utilized within the realm of Chinese typography. This Unicode character represents a horizontal stroke, a fundamental building block in traditional Chinese characters. The CJK Stroke HP serves an essential function in digital text for typesetting purposes, as it assists in accurately rendering and distinguishing various Chinese characters. Its importance lies in the precise positioning of strokes in traditional Chinese characters, which are composed of horizontal, vertical, and oblique lines. In this context, the CJK Stroke HP contributes to maintaining the visual integrity and legibility of traditional Chinese text in digital environments.

How to type the symbol on Windows

Hold Alt and type 12743 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+31C7. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+31C7 to binary: 00110001 11000111. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100011 10000111 10000111