HANGZHOU NUMERAL THREE·U+3023

Character Information

Code Point
U+3023
HEX
3023
Unicode Plane
Basic Multilingual Plane
Category
Letter Number

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E3 80 A3
11100011 10000000 10100011
UTF16 (big Endian)
30 23
00110000 00100011
UTF16 (little Endian)
23 30
00100011 00110000
UTF32 (big Endian)
00 00 30 23
00000000 00000000 00110000 00100011
UTF32 (little Endian)
23 30 00 00
00100011 00110000 00000000 00000000
HTML Entity
〣
URI Encoded
%E3%80%A3

Description

U+3023 is the Unicode character code for "Hangzhou Numeral Three". It is commonly used in digital text as a numerical representation within the Hangzhou numeral system, which is an ancient Chinese numeral system originating from the city of Hangzhou. This numeral system is distinct from other Chinese numerals such as the traditional Chinese characters for numbers or the more widely-used Arabic numerals in contemporary use. The Hangzhou numeral system consists of 10 unique symbols, including U+3023 (Hangzhou Numeral Three), which visually resembles a horizontal line with an upward-pointing stroke at the left end. While not as widely used today as other numerals, U+3023 remains significant for scholars and historians interested in ancient Chinese culture, providing insights into mathematical practices and cultural expressions from a bygone era.

How to type the symbol on Windows

Hold Alt and type 12323 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+3023. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+3023 to binary: 00110000 00100011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100011 10000000 10100011