LEFT BLACK LENTICULAR BRACKET·U+3010

Character Information

Code Point
U+3010
HEX
3010
Unicode Plane
Basic Multilingual Plane
Category
Open Punctuation

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E3 80 90
11100011 10000000 10010000
UTF16 (big Endian)
30 10
00110000 00010000
UTF16 (little Endian)
10 30
00010000 00110000
UTF32 (big Endian)
00 00 30 10
00000000 00000000 00110000 00010000
UTF32 (little Endian)
10 30 00 00
00010000 00110000 00000000 00000000
HTML Entity
【
URI Encoded
%E3%80%90

Description

The Unicode character U+3010, known as the Left Black Lenticular Bracket, is a specialized typographic symbol that plays a specific role in digital text. Its primary function lies in mathematical and scientific notation, where it is used to enclose and delimit sequences of content within a single entity. The Left Black Lenticular Bracket typically pairs with its right-facing counterpart (U+3011) to create an enclosure for such sequences. In this context, the character serves as an alternative to the more commonly used square or round brackets, offering a distinct visual style for specific applications. While it may not be prevalent in everyday digital text, its usage can be found in specialized fields like mathematics, computer science, and certain areas of linguistics where unique typographical representation is required.

How to type the symbol on Windows

Hold Alt and type 12304 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+3010. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+3010 to binary: 00110000 00010000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100011 10000000 10010000