RIGHT WHITE LENTICULAR BRACKET·U+3017

Character Information

Code Point
U+3017
HEX
3017
Unicode Plane
Basic Multilingual Plane
Category
Close Punctuation

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E3 80 97
11100011 10000000 10010111
UTF16 (big Endian)
30 17
00110000 00010111
UTF16 (little Endian)
17 30
00010111 00110000
UTF32 (big Endian)
00 00 30 17
00000000 00000000 00110000 00010111
UTF32 (little Endian)
17 30 00 00
00010111 00110000 00000000 00000000
HTML Entity
〗
URI Encoded
%E3%80%97

Description

The Unicode character U+3017, known as the RIGHT WHITE LENTICULAR BRACKET, is a lesser-known symbol primarily used in digital text for its specific typographic characteristics. This unique symbol has a lenticular shape and serves as a right white variant of the regular white square bracket. In digital text, it can be employed to delimit or enclose segments of text, similar to the usage of standard square brackets. However, due to its rarity in everyday use, the RIGHT WHITE LENTICULAR BRACKET is not widely recognized and may not have significant cultural, linguistic, or technical contexts. Nonetheless, it remains an intriguing example of the vast diversity within Unicode character sets, demonstrating the versatility and flexibility of digital typography in representing a wide range of symbols and characters for various uses.

How to type the symbol on Windows

Hold Alt and type 12311 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+3017. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+3017 to binary: 00110000 00010111. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100011 10000000 10010111