COMBINING LATIN SMALL LETTER U WITH DIAERESIS·U+1DF4

Character Information

Code Point
U+1DF4
HEX
1DF4
Unicode Plane
Basic Multilingual Plane
Category
Nonspacing Mark

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B7 B4
11100001 10110111 10110100
UTF16 (big Endian)
1D F4
00011101 11110100
UTF16 (little Endian)
F4 1D
11110100 00011101
UTF32 (big Endian)
00 00 1D F4
00000000 00000000 00011101 11110100
UTF32 (little Endian)
F4 1D 00 00
11110100 00011101 00000000 00000000
HTML Entity
ᷴ
URI Encoded
%E1%B7%B4

Description

The Unicode character U+1DF4, known as the COMBINING LATIN SMALL LETTER U WITH DIAERESIS, is a specialized glyph that plays a crucial role in digital text representation. This character is often used to provide an accentuated version of the lowercase letter 'u', forming the distinct and unique sound 'ü'. In linguistic contexts where the character is utilized, it signifies a specific phonetic shift within certain languages, such as German or Dutch, where the diaeresis (also referred to as an umlaut) marks a change in vowel sound. The use of U+1DF4 is primarily technical and serves to ensure accurate digital text rendering across various platforms and devices, adhering to Unicode standards for typographical consistency. In the realm of digital text, the COMBINING LATIN SMALL LETTER U WITH DIAERESIS contributes to effective communication by providing a precise representation of specific linguistic nuances within text content.

How to type the symbol on Windows

Hold Alt and type 7668 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1DF4. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1DF4 to binary: 00011101 11110100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110111 10110100