COPTIC CAPITAL LETTER OLD COPTIC GANGIA·U+2CD6

Character Information

Code Point
U+2CD6
HEX
2CD6
Unicode Plane
Basic Multilingual Plane
Category
Uppercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 B3 96
11100010 10110011 10010110
UTF16 (big Endian)
2C D6
00101100 11010110
UTF16 (little Endian)
D6 2C
11010110 00101100
UTF32 (big Endian)
00 00 2C D6
00000000 00000000 00101100 11010110
UTF32 (little Endian)
D6 2C 00 00
11010110 00101100 00000000 00000000
HTML Entity
Ⳗ
URI Encoded
%E2%B3%96

Description

The Unicode character U+2CD6, COPTIC CAPITAL LETTER OLD COPTIC GANGIA, is a significant symbol in the digital representation of the Coptic language, which was primarily used by the ancient Egyptian Christians for religious and liturgical purposes. It holds great importance as part of the Sahidic dialect's alphabet, one of the most widely spoken dialects of the Coptic language. As a capital letter in this unique alphabet, U+2CD6 serves a vital role in transcribing and translating religious texts and historical documents from the Coptic period (circa 4th-13th century AD). The character's presence within digital text enables scholars, researchers, and enthusiasts alike to access and study these ancient manuscripts more accurately and efficiently. Furthermore, it helps preserve the rich cultural heritage of the Coptic people and their language while fostering a deeper understanding of the historical context in which this unique script was developed.

How to type the symbol on Windows

Hold Alt and type 11478 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2CD6. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2CD6 to binary: 00101100 11010110. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10110011 10010110