CIRCLED LATIN SMALL LETTER I·U+24D8

Character Information

Code Point
U+24D8
HEX
24D8
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 93 98
11100010 10010011 10011000
UTF16 (big Endian)
24 D8
00100100 11011000
UTF16 (little Endian)
D8 24
11011000 00100100
UTF32 (big Endian)
00 00 24 D8
00000000 00000000 00100100 11011000
UTF32 (little Endian)
D8 24 00 00
11011000 00100100 00000000 00000000
HTML Entity
ⓘ
URI Encoded
%E2%93%98

Description

U+24D8, known as the "CIRCLED LATIN SMALL LETTER I", is a typographical character commonly found in digital text. It serves to represent the lowercase Latin letter 'i' encased within a circle, often used to denote a particular stylistic choice or emphasis. Although it may not be widely utilized in everyday language usage, the CIRCLED LATIN SMALL LETTER I plays a significant role in typography and design where it can highlight textual elements or indicate special status. Its primary use is in digital environments where fonts support Unicode, ensuring clarity and consistency of representation across various devices and platforms. In summary, U+24D8 offers an alternative visual expression for the lowercase Latin letter 'i', used in typography to signify emphasis or stylistic choice, and relies on digital environments with Unicode-supporting fonts for accurate representation.

How to type the symbol on Windows

Hold Alt and type 9432 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+24D8. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+24D8 to binary: 00100100 11011000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10010011 10011000