DIGIT ONE FULL STOP·U+2488

Character Information

Code Point
U+2488
HEX
2488
Unicode Plane
Basic Multilingual Plane
Category
Other Number

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 92 88
11100010 10010010 10001000
UTF16 (big Endian)
24 88
00100100 10001000
UTF16 (little Endian)
88 24
10001000 00100100
UTF32 (big Endian)
00 00 24 88
00000000 00000000 00100100 10001000
UTF32 (little Endian)
88 24 00 00
10001000 00100100 00000000 00000000
HTML Entity
⒈
URI Encoded
%E2%92%88

Description

The Unicode character U+2488, known as DIGIT ONE FULL STOP, is a typographical symbol that combines the appearance of the numeral '1' with a period (full stop). This unique glyph finds its primary application in digital text for creating a distinct visual marker or bullet point. While it may not hold significant linguistic value across different cultures and languages, it serves a specific purpose in design and typography, offering an alternative to traditional bullets or numbers when used in lists or other enumerated content. The DIGIT ONE FULL STOP character can be found within the "Combining Diacritical Marks for Use with the Arabic Presentation Forms" block of Unicode, indicating its specialized use in typographic contexts.

How to type the symbol on Windows

Hold Alt and type 9352 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2488. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2488 to binary: 00100100 10001000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10010010 10001000