PARENTHESIZED LATIN SMALL LETTER K·U+24A6

Character Information

Code Point
U+24A6
HEX
24A6
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 92 A6
11100010 10010010 10100110
UTF16 (big Endian)
24 A6
00100100 10100110
UTF16 (little Endian)
A6 24
10100110 00100100
UTF32 (big Endian)
00 00 24 A6
00000000 00000000 00100100 10100110
UTF32 (little Endian)
A6 24 00 00
10100110 00100100 00000000 00000000
HTML Entity
⒦
URI Encoded
%E2%92%A6

Description

U+24A6 is a typographical character representing the lowercase Latin letter 'k' within parentheses. In the realm of Unicode and digital text, this unique symbol serves as a distinct visual identifier for specific linguistic or technical contexts. The primary usage of U+24A6 is to denote the presence of the letter 'k' in situations where typographical conventions require enclosing letters within parentheses for clarity or emphasis. It has found applications in fields such as linguistics, typeface design, and digital media production, where the need arises to highlight specific letter forms or contrast them with other characters.

How to type the symbol on Windows

Hold Alt and type 9382 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+24A6. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+24A6 to binary: 00100100 10100110. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10010010 10100110