PARENTHESIZED LATIN SMALL LETTER M·U+24A8

Character Information

Code Point
U+24A8
HEX
24A8
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 92 A8
11100010 10010010 10101000
UTF16 (big Endian)
24 A8
00100100 10101000
UTF16 (little Endian)
A8 24
10101000 00100100
UTF32 (big Endian)
00 00 24 A8
00000000 00000000 00100100 10101000
UTF32 (little Endian)
A8 24 00 00
10101000 00100100 00000000 00000000
HTML Entity
⒨
URI Encoded
%E2%92%A8

Description

U+24A8 is the Unicode code point for the "PARENTHESIZED LATIN SMALL LETTER M" character, which is a typographic symbol used in digital text. It is typically used to represent the lowercase letter 'm' within parentheses, often for emphasizing or highlighting its presence in a specific context. This character holds significance in linguistic and cultural settings where emphasis on particular letters or phonemes is essential, such as in transcription work, foreign language learning, or orthography studies. In technical contexts, it may be used to denote specific rules or concepts within programming languages or textual representations of data structures. However, the usage of U+24A8 remains limited due to its relatively recent addition to the Unicode standard and the absence of widespread adoption in typical text applications.

How to type the symbol on Windows

Hold Alt and type 9384 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+24A8. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+24A8 to binary: 00100100 10101000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10010010 10101000