PARENTHESIZED HANGUL SIOS A·U+3214

Character Information

Code Point
U+3214
HEX
3214
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E3 88 94
11100011 10001000 10010100
UTF16 (big Endian)
32 14
00110010 00010100
UTF16 (little Endian)
14 32
00010100 00110010
UTF32 (big Endian)
00 00 32 14
00000000 00000000 00110010 00010100
UTF32 (little Endian)
14 32 00 00
00010100 00110010 00000000 00000000
HTML Entity
㈔
URI Encoded
%E3%88%94

Description

U+3214 is a typographic character representing the Parenthesized Hangul Siost (PARENTHESIZED HANGUL SIOS A) in Unicode. In digital text, this character serves to denote a specific phoneme or sound in the Korean language, which has four distinct parenthesized forms, corresponding to the U+3214 to U+3217 range in Unicode. The Parenthesized Hangul Siost A character plays a significant role in accurate transcription and translation of Korean text, facilitating more precise communication across languages by clearly representing these unique sounds. Due to its importance in linguistic representation, the U+3214 character is widely used in digital texts involving Korean language, particularly those related to linguistics, translations, and localization efforts.

How to type the symbol on Windows

Hold Alt and type 12820 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+3214. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+3214 to binary: 00110010 00010100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100011 10001000 10010100