DOUBLE LOW LINE·U+2017

Character Information

Code Point
U+2017
HEX
2017
Unicode Plane
Basic Multilingual Plane
Category
Other Punctuation

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 80 97
11100010 10000000 10010111
UTF16 (big Endian)
20 17
00100000 00010111
UTF16 (little Endian)
17 20
00010111 00100000
UTF32 (big Endian)
00 00 20 17
00000000 00000000 00100000 00010111
UTF32 (little Endian)
17 20 00 00
00010111 00100000 00000000 00000000
HTML Entity
‗
URI Encoded
%E2%80%97

Description

The Unicode character U+2017 represents the "DOUBLE LOW LINE". This character is commonly used in digital text to indicate an interruption or a pause within a sentence. Typically, it is used to separate sections of a text or to denote a break when quoting material from different sources. While its usage may be less prevalent in everyday digital communication, the double low line has a significant role in typography, where it helps improve readability and maintain consistency in formatting. It also serves as an important tool for preserving the accuracy of information when reproducing or quoting text from various sources, ensuring proper attribution and preventing misunderstandings.

How to type the symbol on Windows

Hold Alt and type 8215 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2017. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2017 to binary: 00100000 00010111. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10000000 10010111