GUJARATI DIGIT SIX·U+0AEC

Character Information

Code Point
U+0AEC
HEX
0AEC
Unicode Plane
Basic Multilingual Plane
Category
Decimal Digit Number

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E0 AB AC
11100000 10101011 10101100
UTF16 (big Endian)
0A EC
00001010 11101100
UTF16 (little Endian)
EC 0A
11101100 00001010
UTF32 (big Endian)
00 00 0A EC
00000000 00000000 00001010 11101100
UTF32 (little Endian)
EC 0A 00 00
11101100 00001010 00000000 00000000
HTML Entity
૬
URI Encoded
%E0%AB%AC

Description

The Gujarati digit six, represented by the Unicode character U+0AEC, plays a significant role in digital text within the Gujarati script. As one of ten digits used to form numerals in this language, it serves a crucial function in numerical expression and calculation. The Gujarati script is primarily used in the Indian state of Gujarat and the surrounding regions, with Gujarati being the mother tongue for approximately 45 million people. This script belongs to the Indic family of scripts and is derived from the Brahmi script, which further developed into various regional scripts throughout India. In a digital context, U+0AEC enables accurate representation and communication of numerical values in Gujarati text, facilitating efficient data exchange and processing within cultural, linguistic, and technical domains.

How to type the symbol on Windows

Hold Alt and type 2796 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+0AEC. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+0AEC to binary: 00001010 11101100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100000 10101011 10101100