GUJARATI LETTER II·U+0A88

Character Information

Code Point
U+0A88
HEX
0A88
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E0 AA 88
11100000 10101010 10001000
UTF16 (big Endian)
0A 88
00001010 10001000
UTF16 (little Endian)
88 0A
10001000 00001010
UTF32 (big Endian)
00 00 0A 88
00000000 00000000 00001010 10001000
UTF32 (little Endian)
88 0A 00 00
10001000 00001010 00000000 00000000
HTML Entity
ઈ
URI Encoded
%E0%AA%88

Description

U+0A88, or Gujarati Letter II (જ), is a character in the Gujarati script, which belongs to the Indic family of scripts. It plays a crucial role in digital text as it helps represent the Gujarati language, spoken primarily in the Indian state of Gujarat and by the Gujarati diaspora worldwide. Gujarati Letter II is used to transcribe various sounds and phonemes specific to the Gujarati language, enabling accurate communication and preservation of cultural identity. The character is essential for text processing, translation, and digitization efforts aimed at making Gujarati literature, media, and resources accessible globally. In typography, it contributes to maintaining the visual harmony and legibility of texts in the Gujarati script.

How to type the symbol on Windows

Hold Alt and type 2696 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+0A88. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+0A88 to binary: 00001010 10001000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100000 10101010 10001000