GUJARATI VOWEL SIGN II·U+0AC0

Character Information

Code Point
U+0AC0
HEX
0AC0
Unicode Plane
Basic Multilingual Plane
Category
Spacing Mark

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E0 AB 80
11100000 10101011 10000000
UTF16 (big Endian)
0A C0
00001010 11000000
UTF16 (little Endian)
C0 0A
11000000 00001010
UTF32 (big Endian)
00 00 0A C0
00000000 00000000 00001010 11000000
UTF32 (little Endian)
C0 0A 00 00
11000000 00001010 00000000 00000000
HTML Entity
ી
URI Encoded
%E0%AB%80

Description

U+0AC0 Gujarati Vowel Sign II is a crucial character within the Gujarat script, primarily utilized for phonetic and typographic distinctions in written language. In digital text, it plays a significant role by serving as an integral component of various Gujarati words. The character provides clarity in the context of vowels, enabling readers to comprehend and distinguish words with precision. It is worth noting that this unique script holds historical and cultural significance for the Gujarat community, who have relied on it for centuries for written communication. The Gujarati script, of which U+0AC0 is a part, is also technically remarkable for its ability to represent a wide range of sounds, making it an essential tool in linguistic studies and preservation efforts. Overall, U+0AC0 Gujarati Vowel Sign II is a critical character that contributes to the richness and diversity of digital text, especially within the realm of the Gujarat language.

How to type the symbol on Windows

Hold Alt and type 2752 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+0AC0. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+0AC0 to binary: 00001010 11000000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100000 10101011 10000000