HANGUL CHOSEONG SSANGSIOS·U+110A

Character Information

Code Point
U+110A
HEX
110A
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 84 8A
11100001 10000100 10001010
UTF16 (big Endian)
11 0A
00010001 00001010
UTF16 (little Endian)
0A 11
00001010 00010001
UTF32 (big Endian)
00 00 11 0A
00000000 00000000 00010001 00001010
UTF32 (little Endian)
0A 11 00 00
00001010 00010001 00000000 00000000
HTML Entity
ᄊ
URI Encoded
%E1%84%8A

Description

U+110A, known as Hangul Choseong Ssangsios, is a critical character within the Korean alphabet system. In digital text, it primarily serves as a component in forming various Hangul consonants, specifically in combination with other Hangul Jamos. The Hangul Choseong Ssangsios belongs to the Hangul Choseong group of consonant-forming characters and holds an essential position in constructing the Korean language's complex syllabary system. This character is indispensable for accurate representation and communication of the Korean language's diverse vocabulary and expressions, making it a vital building block in Unicode and digital text systems.

How to type the symbol on Windows

Hold Alt and type 4362 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+110A. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+110A to binary: 00010001 00001010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10000100 10001010