HANGUL JONGSEONG NIEUN-TIKEUT·U+11C6

Character Information

Code Point
U+11C6
HEX
11C6
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 87 86
11100001 10000111 10000110
UTF16 (big Endian)
11 C6
00010001 11000110
UTF16 (little Endian)
C6 11
11000110 00010001
UTF32 (big Endian)
00 00 11 C6
00000000 00000000 00010001 11000110
UTF32 (little Endian)
C6 11 00 00
11000110 00010001 00000000 00000000
HTML Entity
ᇆ
URI Encoded
%E1%87%86

Description

The Hangul Jongseong Nieun-Tikeut (U+11C6) is a significant character in the Korean alphabet system, Hangul. As a jongseong, it represents an initial consonant cluster in the Korean language and plays a crucial role in the construction of syllable blocks called jamo. The Nieun-Tikeut specifically denotes the aspirated "n" sound when followed by certain vowels, contributing to the rich phonetic diversity of the Korean language. This character holds immense cultural and linguistic importance as Hangul, of which the U+11C6 character is a part, was developed during the 15th century under the direction of King Sejong the Great to promote literacy among common people in Korea. Today, it remains an integral component of the Korean digital text, showcasing the robustness and adaptability of Hangul in the modern era.

How to type the symbol on Windows

Hold Alt and type 4550 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+11C6. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+11C6 to binary: 00010001 11000110. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10000111 10000110