HANGUL JONGSEONG RIEUL-SSANGSIOS·U+11D6

Character Information

Code Point
U+11D6
HEX
11D6
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 87 96
11100001 10000111 10010110
UTF16 (big Endian)
11 D6
00010001 11010110
UTF16 (little Endian)
D6 11
11010110 00010001
UTF32 (big Endian)
00 00 11 D6
00000000 00000000 00010001 11010110
UTF32 (little Endian)
D6 11 00 00
11010110 00010001 00000000 00000000
HTML Entity
ᇖ
URI Encoded
%E1%87%96

Description

The Unicode character U+11D6 represents 'Hangul Jongseong Rieul-ssangsios' in the Hangul Compatibility Jamo block. It is primarily used in digital text, particularly in the Korean language system, where it serves as a component of complex syllables. In this context, it forms part of the Hangul script, which is the native writing system of the Korean language. Notably, each Jongseong character works with a combination of a Dikya (vowel) and one or two Jamo (consonant) characters to form a single syllable block, enabling the creation of an extensive range of phonetic and semantic combinations in written Korean. U+11D6 plays a crucial role in maintaining the linguistic accuracy and consistency within digital texts, helping preserve the rich history and culture of the Korean language.

How to type the symbol on Windows

Hold Alt and type 4566 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+11D6. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+11D6 to binary: 00010001 11010110. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10000111 10010110