HANGUL JUNGSEONG AE·U+1162

Character Information

Code Point
U+1162
HEX
1162
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 85 A2
11100001 10000101 10100010
UTF16 (big Endian)
11 62
00010001 01100010
UTF16 (little Endian)
62 11
01100010 00010001
UTF32 (big Endian)
00 00 11 62
00000000 00000000 00010001 01100010
UTF32 (little Endian)
62 11 00 00
01100010 00010001 00000000 00000000
HTML Entity
ᅢ
URI Encoded
%E1%85%A2

Description

The character U+1162 (HANGUL JUNGSEONG AE) is a critical component of the Korean language, specifically within the Hangul writing system. In digital text, it plays a significant role as part of composite syllable blocks in Korean typography, combining with other Hangul letters to form complex syllables. The Hangul Jungseong AE character contributes to the rich linguistic and cultural heritage of Korea, showcasing the intricacies of its phonetic system. Its precise usage adheres to strict rules, which ensures that it is employed accurately within Korean digital text. Due to its importance in the Hangul script, U+1162 (HANGUL JUNGSEONG AE) helps maintain the consistency and clarity of written communication in Korean language across various digital platforms.

How to type the symbol on Windows

Hold Alt and type 4450 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1162. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1162 to binary: 00010001 01100010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10000101 10100010