LATIN LETTER REVERSED GLOTTAL STOP WITH STROKE·U+02A2

ʢ

Character Information

Code Point
U+02A2
HEX
02A2
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
CA A2
11001010 10100010
UTF16 (big Endian)
02 A2
00000010 10100010
UTF16 (little Endian)
A2 02
10100010 00000010
UTF32 (big Endian)
00 00 02 A2
00000000 00000000 00000010 10100010
UTF32 (little Endian)
A2 02 00 00
10100010 00000010 00000000 00000000
HTML Entity
ʢ
URI Encoded
%CA%A2

Description

The Unicode character U+02A2, known as "LATIN LETTER REVERSED GLOTTAL STOP WITH STROKE," represents a unique typographic element in digital text. This character is often used in various contexts to symbolize an upside-down glottal stop, which is a type of consonantal sound produced by blocking the flow of air at the back of the throat. The presence of a stroke in this character distinguishes it from the standard "LATIN LETTER REVERSED GLOTTAL STOP" (U+0261). It may be employed to add visual interest, demonstrate linguistic or cultural nuances, or as an artistic flourish in typography and graphic design. However, its usage is relatively rare due to the lack of widespread demand for a reversed glottal stop with a stroke in most languages.

How to type the ʢ symbol on Windows

Hold Alt and type 0674 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character ʢ has the Unicode code point U+02A2. In UTF-8, it is encoded using 2 bytes because its codepoint is in the range of 0x0080 to 0x07ff.

    Therefore we know that the UTF-8 encoding will be done over 11 bits within the final 16 bits and that it will have the format: 110xxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+02A2 to binary: 00000010 10100010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11001010 10100010