LATIN SMALL LETTER HENG WITH HOOK·U+0267

ɧ

Character Information

Code Point
U+0267
HEX
0267
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
C9 A7
11001001 10100111
UTF16 (big Endian)
02 67
00000010 01100111
UTF16 (little Endian)
67 02
01100111 00000010
UTF32 (big Endian)
00 00 02 67
00000000 00000000 00000010 01100111
UTF32 (little Endian)
67 02 00 00
01100111 00000010 00000000 00000000
HTML Entity
ɧ
URI Encoded
%C9%A7

Description

The Unicode character U+0267 represents the Latin Small Letter Heng with Hook, a unique glyph that is rarely used in modern typography. This letter is primarily found in the Manuscript of the Şirvan Gospel, a medieval manuscript of the Book of Psalms, written in Old Georgian script between the 10th and 12th centuries. It was discovered in the Caucasus region and is of great cultural significance due to its historical context. The letter "heng" (ჰ) has a distinctive hook-like form at the top that distinguishes it from other Latin letters, which may contribute to its rarity in contemporary digital text. Despite this, typography enthusiasts and linguists continue to study and appreciate the unique characteristics of the U+0267, as it offers a glimpse into the rich history of written communication.

How to type the ɧ symbol on Windows

Hold Alt and type 0615 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character ɧ has the Unicode code point U+0267. In UTF-8, it is encoded using 2 bytes because its codepoint is in the range of 0x0080 to 0x07ff.

    Therefore we know that the UTF-8 encoding will be done over 11 bits within the final 16 bits and that it will have the format: 110xxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+0267 to binary: 00000010 01100111. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11001001 10100111