LATIN SMALL LETTER LS DIGRAPH·U+02AA

ʪ

Character Information

Code Point
U+02AA
HEX
02AA
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
CA AA
11001010 10101010
UTF16 (big Endian)
02 AA
00000010 10101010
UTF16 (little Endian)
AA 02
10101010 00000010
UTF32 (big Endian)
00 00 02 AA
00000000 00000000 00000010 10101010
UTF32 (little Endian)
AA 02 00 00
10101010 00000010 00000000 00000000
HTML Entity
ʪ
URI Encoded
%CA%AA

Description

U+02AA, the Latin Small Letter Ls Digraph, is a unique character in Unicode that plays a specific role in digital text. It is a diacritic, which means it serves to modify another letter rather than standing alone as an independent character. Specifically, the Latin Small Letter Ls Digraph is used to represent a modified version of the lowercase letter 'L', appearing after a single lowercase 'l' to create a distinct symbol. This digraph is commonly employed in the construction of certain types of typography and ornamental scripts, where it adds a touch of elegance or visual interest to text passages. While its usage may be less widespread in everyday digital communication, the Latin Small Letter Ls Digraph still holds cultural and technical significance for those who appreciate intricate letterforms and historical script styles.

How to type the ʪ symbol on Windows

Hold Alt and type 0682 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character ʪ has the Unicode code point U+02AA. In UTF-8, it is encoded using 2 bytes because its codepoint is in the range of 0x0080 to 0x07ff.

    Therefore we know that the UTF-8 encoding will be done over 11 bits within the final 16 bits and that it will have the format: 110xxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+02AA to binary: 00000010 10101010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11001010 10101010