LATIN SMALL LETTER N WITH LEFT HOOK·U+0272

ɲ

Character Information

Code Point
U+0272
HEX
0272
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
C9 B2
11001001 10110010
UTF16 (big Endian)
02 72
00000010 01110010
UTF16 (little Endian)
72 02
01110010 00000010
UTF32 (big Endian)
00 00 02 72
00000000 00000000 00000010 01110010
UTF32 (little Endian)
72 02 00 00
01110010 00000010 00000000 00000000
HTML Entity
ɲ
URI Encoded
%C9%B2

Description

The Unicode character U+0272, known as the Latin Small Letter N with Left Hook (Ⅎ), primarily serves a role in digital text as a typographical variation of the letter "N". It is a part of the Extended Latino-1 Supplement block of Unicode, which includes characters used for various European and non-Latin scripts. The character has no specific cultural, linguistic, or technical context associated with it. However, it can be used to add visual interest or uniqueness in typographic design, as well as in text messaging or digital communication where the use of this particular form of "N" might convey a certain meaning or sentiment. In summary, U+0272 is a typographical variant of the letter "N", used for unique design purposes and has no cultural or linguistic significance.

How to type the ɲ symbol on Windows

Hold Alt and type 0626 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character ɲ has the Unicode code point U+0272. In UTF-8, it is encoded using 2 bytes because its codepoint is in the range of 0x0080 to 0x07ff.

    Therefore we know that the UTF-8 encoding will be done over 11 bits within the final 16 bits and that it will have the format: 110xxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+0272 to binary: 00000010 01110010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11001001 10110010