KANGXI RADICAL CAVE·U+2F73

Character Information

Code Point
U+2F73
HEX
2F73
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 BD B3
11100010 10111101 10110011
UTF16 (big Endian)
2F 73
00101111 01110011
UTF16 (little Endian)
73 2F
01110011 00101111
UTF32 (big Endian)
00 00 2F 73
00000000 00000000 00101111 01110011
UTF32 (little Endian)
73 2F 00 00
01110011 00101111 00000000 00000000
HTML Entity
⽳
URI Encoded
%E2%BD%B3

Description

The Unicode character U+2F73 is known as the Kangxi Radical Cave. In digital text, this character typically represents a specific component of Chinese characters called a radical. A radical is a group of strokes that form the core structure of a character and can be associated with a particular meaning or concept. The Kangxi Radical Cave, derived from the Kangxi Dictionary (康熙字典), is one of the 501 radicals used in Chinese character classification. Although its use has diminished with advancements in information technology and digital text processing, it still holds significance for understanding the etymology and formation of complex Chinese characters. The Kangxi Radical Cave symbol is often employed by linguists, typographers, and those interested in Chinese orthography to study and analyze Chinese characters.

How to type the symbol on Windows

Hold Alt and type 12147 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2F73. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2F73 to binary: 00101111 01110011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10111101 10110011