KANGXI RADICAL DOTTED CLIFF·U+2F34

Character Information

Code Point
U+2F34
HEX
2F34
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 BC B4
11100010 10111100 10110100
UTF16 (big Endian)
2F 34
00101111 00110100
UTF16 (little Endian)
34 2F
00110100 00101111
UTF32 (big Endian)
00 00 2F 34
00000000 00000000 00101111 00110100
UTF32 (little Endian)
34 2F 00 00
00110100 00101111 00000000 00000000
HTML Entity
⼴
URI Encoded
%E2%BC%B4

Description

The Unicode character U+2F34, known as the Kangxi Radical Dotted Cliff, holds a significant place in the realm of digital typography and text encoding. It is primarily used to represent a specific radical or stroke order within the Chinese script system, specifically referring to the radical "氵" (Cliff) with an added dot notation. This character serves as a valuable tool for learners and scholars of Chinese characters, aiding in the understanding and differentiation of various character forms and structures. The Kangxi Radical Dotted Cliff provides a clear visual representation of these intricate details, contributing to the precision and accuracy required for mastery of the language. In addition to its utility within linguistic studies, this character is also crucial for digital text processing, as it allows for the proper classification and organization of characters in various text databases and software applications.

How to type the symbol on Windows

Hold Alt and type 12084 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2F34. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2F34 to binary: 00101111 00110100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10111100 10110100