KANGXI RADICAL HAND·U+2F3F

⼿

Character Information

Code Point
U+2F3F
HEX
2F3F
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 BC BF
11100010 10111100 10111111
UTF16 (big Endian)
2F 3F
00101111 00111111
UTF16 (little Endian)
3F 2F
00111111 00101111
UTF32 (big Endian)
00 00 2F 3F
00000000 00000000 00101111 00111111
UTF32 (little Endian)
3F 2F 00 00
00111111 00101111 00000000 00000000
HTML Entity
⼿
URI Encoded
%E2%BC%BF

Description

The character U+2F3F, also known as KANGXI RADICAL HAND, is a unique symbol within the Unicode standard that holds significant importance in digital text. Its primary role lies in the representation of ancient Chinese characters, which are structured using a system called "Kangxi radicals." These radicals serve as a hierarchical classification system for Chinese characters, facilitating their organization and lookup in dictionaries. The KANGXI RADICAL HAND specifically refers to the hand-shaped radical, which is used to denote actions related to hands or manipulation of objects. In digital text, this character often appears when using tools like input methods or character encoders that incorporate Kangxi radicals for simplifying the process of finding and selecting characters in the written Chinese language.

How to type the ⼿ symbol on Windows

Hold Alt and type 12095 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character ⼿ has the Unicode code point U+2F3F. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2F3F to binary: 00101111 00111111. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10111100 10111111