KANGXI RADICAL HORN·U+2F93

Character Information

Code Point
U+2F93
HEX
2F93
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 BE 93
11100010 10111110 10010011
UTF16 (big Endian)
2F 93
00101111 10010011
UTF16 (little Endian)
93 2F
10010011 00101111
UTF32 (big Endian)
00 00 2F 93
00000000 00000000 00101111 10010011
UTF32 (little Endian)
93 2F 00 00
10010011 00101111 00000000 00000000
HTML Entity
⾓
URI Encoded
%E2%BE%93

Description

The Kangxi Radical Horn (U+2F93) is a unique character in Unicode, primarily used as a reference for the organization of Chinese characters. It represents the "horn" component, one of the 560 Kangxi radicals that make up the majority of Chinese characters. In digital text, it serves to categorize and facilitate the understanding of Chinese characters by indicating which part of the character is derived from the horn radical. This aids in the process of character composition and learning, as well as in the indexing and retrieval of characters within computational systems. The Kangxi Radical Horn holds significance in both linguistic and cultural contexts due to its roots in the traditional system of Chinese character classification developed by the Qing Dynasty scholar Lei Gongpu, which is still widely used today.

How to type the symbol on Windows

Hold Alt and type 12179 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2F93. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2F93 to binary: 00101111 10010011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10111110 10010011