KANGXI RADICAL HORSE·U+2FBA

Character Information

Code Point
U+2FBA
HEX
2FBA
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 BE BA
11100010 10111110 10111010
UTF16 (big Endian)
2F BA
00101111 10111010
UTF16 (little Endian)
BA 2F
10111010 00101111
UTF32 (big Endian)
00 00 2F BA
00000000 00000000 00101111 10111010
UTF32 (little Endian)
BA 2F 00 00
10111010 00101111 00000000 00000000
HTML Entity
⾺
URI Encoded
%E2%BE%BA

Description

The character U+2FBA (KANGXI RADICAL HORSE) is a significant component of the Kangxi Character Dictionary, an essential lexicographical work in Chinese language studies. In digital text, it represents the radical horse, a fundamental building block in the composition of Chinese characters. This radical serves as a phonetic and semantic indicator, helping to classify and analyze characters for educational purposes and character encoding systems like Unicode. The Kangxi Radical Horse is widely used in linguistic research and historical analysis due to its cultural significance and role in traditional Chinese script.

How to type the symbol on Windows

Hold Alt and type 12218 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2FBA. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2FBA to binary: 00101111 10111010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10111110 10111010