KANGXI RADICAL SLICE·U+2F5A

Character Information

Code Point
U+2F5A
HEX
2F5A
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 BD 9A
11100010 10111101 10011010
UTF16 (big Endian)
2F 5A
00101111 01011010
UTF16 (little Endian)
5A 2F
01011010 00101111
UTF32 (big Endian)
00 00 2F 5A
00000000 00000000 00101111 01011010
UTF32 (little Endian)
5A 2F 00 00
01011010 00101111 00000000 00000000
HTML Entity
⽚
URI Encoded
%E2%BD%9A

Description

The Kangxi Radical Slice (U+2F5A) is a unique character within the Unicode Standard that holds significant importance for scholars and experts in typography, particularly those studying Chinese characters. This particular character serves as a visual indicator or marker within the context of the Kangxi Dictionary, which was compiled during the Kangxi era of the Qing Dynasty (1644-1911) in China. The character is used to denote when a character consists only of the radical associated with that specific entry, rather than an additional or combined element within the character. In digital text, its typical usage is to provide context and aid in understanding the structure and composition of Chinese characters for research purposes or for those studying the intricacies of the Chinese writing system.

How to type the symbol on Windows

Hold Alt and type 12122 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2F5A. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2F5A to binary: 00101111 01011010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10111101 10011010