KHMER SYMBOL BUON ROC·U+19F4

Character Information

Code Point
U+19F4
HEX
19F4
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A7 B4
11100001 10100111 10110100
UTF16 (big Endian)
19 F4
00011001 11110100
UTF16 (little Endian)
F4 19
11110100 00011001
UTF32 (big Endian)
00 00 19 F4
00000000 00000000 00011001 11110100
UTF32 (little Endian)
F4 19 00 00
11110100 00011001 00000000 00000000
HTML Entity
᧴
URI Encoded
%E1%A7%B4

Description

The Unicode character U+19F4, known as the "Khmer Symbol Buon Roc," holds a unique position in the realm of digital text and typography. It is primarily used within the Khmer script system, which is predominantly employed for written communication in Cambodia. The Khmer script, a member of the Brahui family of scripts, has been an essential part of Khmer culture for centuries, and U+19F4 plays a significant role in preserving this cultural heritage in digital formats. Although not widely used, the Buon Roc symbol is a vital element in certain Khmer religious texts and inscriptions, which often incorporate unique symbols to represent abstract concepts or philosophical ideas. As a result, U+19F4 is an essential character in maintaining the linguistic and cultural integrity of the Khmer script within the Unicode standard.

How to type the symbol on Windows

Hold Alt and type 6644 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+19F4. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+19F4 to binary: 00011001 11110100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10100111 10110100