KHMER SYMBOL PRAM-MUOY KOET·U+19E6

Character Information

Code Point
U+19E6
HEX
19E6
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A7 A6
11100001 10100111 10100110
UTF16 (big Endian)
19 E6
00011001 11100110
UTF16 (little Endian)
E6 19
11100110 00011001
UTF32 (big Endian)
00 00 19 E6
00000000 00000000 00011001 11100110
UTF32 (little Endian)
E6 19 00 00
11100110 00011001 00000000 00000000
HTML Entity
᧦
URI Encoded
%E1%A7%A6

Description

The Unicode character U+19E6 represents the "Khmer Symbol Pram-Muoys Koet" (ក្រុមបញ្ឆាត) in the Khmer script, which is the writing system used for the Khmer language spoken primarily in Cambodia. This symbol plays an important role in digital text by representing a specific phonetic or semantic aspect of the language. While not widely known outside of its cultural context, the Pram-Muoys Koet has significant value for native speakers and linguists alike, as it helps preserve the unique characteristics and nuances of the Khmer language. The use of this character demonstrates a deep understanding of the intricacies of the script, which is an essential aspect of maintaining cultural heritage and identity in digital spaces.

How to type the symbol on Windows

Hold Alt and type 6630 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+19E6. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+19E6 to binary: 00011001 11100110. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10100111 10100110