KHMER LETTER CHO·U+1788

Character Information

Code Point
U+1788
HEX
1788
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 9E 88
11100001 10011110 10001000
UTF16 (big Endian)
17 88
00010111 10001000
UTF16 (little Endian)
88 17
10001000 00010111
UTF32 (big Endian)
00 00 17 88
00000000 00000000 00010111 10001000
UTF32 (little Endian)
88 17 00 00
10001000 00010111 00000000 00000000
HTML Entity
ឈ
URI Encoded
%E1%9E%88

Description

The Unicode character U+1788 represents the Khmer letter "Cho". In digital text, this character is used to accurately represent the phonetic sounds and meaning of the Cho letter in written Khmer language. Khmer is the official language of Cambodia and is also spoken in parts of Laos, Thailand, and Vietnam. The script has a rich history dating back to the 9th century, and has been influenced by Sanskrit, Pali, and Chinese characters. U+1788's role in digital text is crucial for maintaining linguistic integrity, as it ensures that Khmer texts are correctly displayed, edited, and transmitted across various digital platforms. The character's accurate representation supports the preservation of cultural heritage and facilitates effective communication among native speakers.

How to type the symbol on Windows

Hold Alt and type 6024 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1788. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1788 to binary: 00010111 10001000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10011110 10001000