KHMER SIGN BANTOC·U+17CB

Character Information

Code Point
U+17CB
HEX
17CB
Unicode Plane
Basic Multilingual Plane
Category
Nonspacing Mark

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 9F 8B
11100001 10011111 10001011
UTF16 (big Endian)
17 CB
00010111 11001011
UTF16 (little Endian)
CB 17
11001011 00010111
UTF32 (big Endian)
00 00 17 CB
00000000 00000000 00010111 11001011
UTF32 (little Endian)
CB 17 00 00
11001011 00010111 00000000 00000000
HTML Entity
់
URI Encoded
%E1%9F%8B

Description

The Unicode character U+17CB, known as the Khmer Sign Bantoc, is a specialized symbol used in the Khmer script. This script is primarily employed for writing the Khmer language, which is spoken by over 20 million people in Cambodia and other parts of Southeast Asia. As part of the Khmer script, U+17CB plays an essential role in digital text, as it contributes to the accurate representation of written content in the Khmer language. The character holds significance in both cultural and linguistic contexts, as it reflects the unique phonetic and structural characteristics of the Khmer script that have evolved over centuries. Despite its importance, U+17CB remains a niche character within the broader spectrum of Unicode characters, utilized primarily by those who are familiar with or study the Khmer language and culture.

How to type the symbol on Windows

Hold Alt and type 6091 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+17CB. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+17CB to binary: 00010111 11001011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10011111 10001011