LATIN CAPITAL LETTER D WITH DOT BELOW·U+1E0C

Character Information

Code Point
U+1E0C
HEX
1E0C
Unicode Plane
Basic Multilingual Plane
Category
Uppercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B8 8C
11100001 10111000 10001100
UTF16 (big Endian)
1E 0C
00011110 00001100
UTF16 (little Endian)
0C 1E
00001100 00011110
UTF32 (big Endian)
00 00 1E 0C
00000000 00000000 00011110 00001100
UTF32 (little Endian)
0C 1E 00 00
00001100 00011110 00000000 00000000
HTML Entity
Ḍ
URI Encoded
%E1%B8%8C

Description

The Unicode character U+1E0C, known as LATIN CAPITAL LETTER D WITH DOT BELOW, plays a significant role in digital typography by providing an alternative representation of the uppercase letter "D" with a distinctive visual feature. This character is particularly useful for creating custom or unique typefaces and designs that deviate from the standard Latin alphabet. Its usage can be seen in various fields such as graphic design, branding, and web design, where it helps convey distinctiveness and creativity. Although this character may not have any specific cultural or linguistic context, its presence in the Unicode Standard signifies the importance of typographic diversity and individuality within digital text.

How to type the symbol on Windows

Hold Alt and type 7692 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1E0C. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1E0C to binary: 00011110 00001100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10111000 10001100