LATIN SMALL LETTER A WITH BREVE AND HOOK ABOVE·U+1EB3

Character Information

Code Point
U+1EB3
HEX
1EB3
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 BA B3
11100001 10111010 10110011
UTF16 (big Endian)
1E B3
00011110 10110011
UTF16 (little Endian)
B3 1E
10110011 00011110
UTF32 (big Endian)
00 00 1E B3
00000000 00000000 00011110 10110011
UTF32 (little Endian)
B3 1E 00 00
10110011 00011110 00000000 00000000
HTML Entity
ẳ
URI Encoded
%E1%BA%B3

Description

The character U+1EB3, known as "LATIN SMALL LETTER A WITH BREVE AND HOOK ABOVE," holds a significant role in digital text by providing an essential function for linguistic expression. This particular Unicode character is specifically designed to represent the combination of two diacritical marks - the breve and the acute accent - on the letter 'a'. The breve, represented as a horizontal line beneath the letter, indicates a short vowel sound, while the hook or acute accent above it, signals a stress on that syllable. This combination is crucial in various languages for accurate pronunciation and to distinguish between different words with similar sequences of letters. In a broader context, U+1EB3 represents the versatility and inclusivity of Unicode, ensuring that digital text accurately reflects the linguistic diversity across the globe.

How to type the symbol on Windows

Hold Alt and type 7859 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1EB3. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1EB3 to binary: 00011110 10110011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10111010 10110011