LATIN SMALL LETTER A WITH CIRCUMFLEX AND HOOK ABOVE·U+1EA9

Character Information

Code Point
U+1EA9
HEX
1EA9
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 BA A9
11100001 10111010 10101001
UTF16 (big Endian)
1E A9
00011110 10101001
UTF16 (little Endian)
A9 1E
10101001 00011110
UTF32 (big Endian)
00 00 1E A9
00000000 00000000 00011110 10101001
UTF32 (little Endian)
A9 1E 00 00
10101001 00011110 00000000 00000000
HTML Entity
ẩ
URI Encoded
%E1%BA%A9

Description

U+1EA9, the Latin Small Letter A with Circumflex and Hook Above, is a unique typographic character primarily used in digital text for its distinctive appearance. It combines two diacritical marks: the circumflex (¨) and the hook above (ˆ). This character is most commonly found in the Occitan language, where it represents the sound [ə]. Its usage helps to maintain linguistic accuracy in written texts that use the Occitan orthography system, which differentiates it from other alphabetic characters. While its primary role is within the realm of Occitan and related languages, the Latin Small Letter A with Circumflex and Hook Above has found occasional use in typographic design for its aesthetic appeal, where it can serve as a unique element to enhance visual interest.

How to type the symbol on Windows

Hold Alt and type 7849 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1EA9. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1EA9 to binary: 00011110 10101001. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10111010 10101001