LATIN SMALL LETTER A WITH HOOK ABOVE·U+1EA3

Character Information

Code Point
U+1EA3
HEX
1EA3
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 BA A3
11100001 10111010 10100011
UTF16 (big Endian)
1E A3
00011110 10100011
UTF16 (little Endian)
A3 1E
10100011 00011110
UTF32 (big Endian)
00 00 1E A3
00000000 00000000 00011110 10100011
UTF32 (little Endian)
A3 1E 00 00
10100011 00011110 00000000 00000000
HTML Entity
ả
URI Encoded
%E1%BA%A3

Description

U+1EA3, also known as Latin Small Letter A with Hook Above, is a unique character in the Unicode system that plays a significant role in digital text. This character represents a modified form of the lowercase letter 'a' from the Latin alphabet, featuring a distinct hook-like addition above it. The primary usage of U+1EA3 lies within typography and linguistic contexts where it serves as an accent mark for specific languages or dialects that utilize this particular diacritical sign. In some instances, it is employed to denote a change in pronunciation or stress within words. Although its application may be relatively niche compared to more commonly used Unicode characters, U+1EA3 contributes to the rich diversity and expressiveness of written communication across various cultures and languages.

How to type the symbol on Windows

Hold Alt and type 7843 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1EA3. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1EA3 to binary: 00011110 10100011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10111010 10100011