LATIN SMALL LETTER B WITH DOT ABOVE·U+1E03

Character Information

Code Point
U+1E03
HEX
1E03
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B8 83
11100001 10111000 10000011
UTF16 (big Endian)
1E 03
00011110 00000011
UTF16 (little Endian)
03 1E
00000011 00011110
UTF32 (big Endian)
00 00 1E 03
00000000 00000000 00011110 00000011
UTF32 (little Endian)
03 1E 00 00
00000011 00011110 00000000 00000000
HTML Entity
ḃ
URI Encoded
%E1%B8%83

Description

U+1E03 is a Unicode character representing the Latin small letter B with dot above (ḃ). In digital text, this character serves as a unique representation of the lowercase 'b' with an accent dot above it. Its usage primarily lies within typography and digital communication, where it may be used to fulfill specific linguistic or stylistic requirements. Although not part of the standard English alphabet, U+1E03 is often utilized in languages such as Samogitian, a dialect spoken in Lithuania, where it plays an essential role in accurate representation of local pronunciation and orthography. In technical contexts, the character may be employed to differentiate between similar-looking characters or for aesthetic purposes. Overall, U+1E03 is a vital element in digital text, contributing to the richness and diversity of human language expression.

How to type the symbol on Windows

Hold Alt and type 7683 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1E03. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1E03 to binary: 00011110 00000011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10111000 10000011