LATIN SMALL LETTER LONG S WITH DIAGONAL STROKE·U+1E9C

Character Information

Code Point
U+1E9C
HEX
1E9C
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 BA 9C
11100001 10111010 10011100
UTF16 (big Endian)
1E 9C
00011110 10011100
UTF16 (little Endian)
9C 1E
10011100 00011110
UTF32 (big Endian)
00 00 1E 9C
00000000 00000000 00011110 10011100
UTF32 (little Endian)
9C 1E 00 00
10011100 00011110 00000000 00000000
HTML Entity
ẜ
URI Encoded
%E1%BA%9C

Description

The Unicode character U+1E9C, known as the "LATIN SMALL LETTER LONG S WITH DIAGONAL STROKE," is a typographic symbol primarily used in digital text for specific linguistic or technical purposes. It is a variant of the letter 's' that features a diagonal stroke originating from its top bar and extending towards the bottom right corner. This unique characteristic sets it apart from the standard lowercase 's.' Although the usage of U+1E9C in written language is relatively uncommon, it can be found in certain specialized contexts such as coding or programming to indicate specific actions or commands. Its existence in Unicode allows for greater diversity and flexibility in digital communication, enabling users to express their ideas and information using a wider range of characters and symbols.

How to type the symbol on Windows

Hold Alt and type 7836 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1E9C. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1E9C to binary: 00011110 10011100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10111010 10011100