LATIN SMALL LETTER N WITH DOT BELOW·U+1E47

Character Information

Code Point
U+1E47
HEX
1E47
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B9 87
11100001 10111001 10000111
UTF16 (big Endian)
1E 47
00011110 01000111
UTF16 (little Endian)
47 1E
01000111 00011110
UTF32 (big Endian)
00 00 1E 47
00000000 00000000 00011110 01000111
UTF32 (little Endian)
47 1E 00 00
01000111 00011110 00000000 00000000
HTML Entity
ṇ
URI Encoded
%E1%B9%87

Description

U+1E47, also known as "LATIN SMALL LETTER N WITH DOT BELOW," is a Unicode character that plays a significant role in digital text representation. Typically used in typography, this character features a small dot placed below the letter 'n'. The presence of the dot distinguishes it from the regular lowercase 'n' (U+006E) and is often employed to convey specific phonetic or linguistic nuances in certain languages that employ diacritical marks. While it does not have a direct correlation with any particular language, it serves as an essential tool for textual representation in contexts where the additional dot below the 'n' signifies a unique sound or pronunciation. The character U+1E47 demonstrates the versatility and expressive capabilities of Unicode, which aims to accommodate diverse scripts and orthographic systems from around the world.

How to type the symbol on Windows

Hold Alt and type 7751 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1E47. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1E47 to binary: 00011110 01000111. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10111001 10000111