LATIN SMALL LETTER O WITH HORN AND HOOK ABOVE·U+1EDF

Character Information

Code Point
U+1EDF
HEX
1EDF
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 BB 9F
11100001 10111011 10011111
UTF16 (big Endian)
1E DF
00011110 11011111
UTF16 (little Endian)
DF 1E
11011111 00011110
UTF32 (big Endian)
00 00 1E DF
00000000 00000000 00011110 11011111
UTF32 (little Endian)
DF 1E 00 00
11011111 00011110 00000000 00000000
HTML Entity
ở
URI Encoded
%E1%BB%9F

Description

The character U+1EDF, also known as Latin Small Letter O with Horn and Hook Above, is a typographical symbol that plays an essential role in digital text representation. This Unicode character is predominantly used in linguistic and cultural contexts, primarily to represent specific phonetic distinctions or accents within certain languages. It can be found in alphabets of various regional dialects and ancient scripts, reflecting the diverse nature of human language expression. As digital communication continues to evolve, the usage of such specialized characters becomes increasingly significant for preserving linguistic authenticity and ensuring accurate representation of speech sounds. By incorporating these characters into digital text, we can bridge cultural gaps and foster greater understanding among different communities.

How to type the symbol on Windows

Hold Alt and type 7903 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1EDF. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1EDF to binary: 00011110 11011111. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10111011 10011111