LATIN SMALL LETTER S WITH DOT BELOW·U+1E63

Character Information

Code Point
U+1E63
HEX
1E63
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B9 A3
11100001 10111001 10100011
UTF16 (big Endian)
1E 63
00011110 01100011
UTF16 (little Endian)
63 1E
01100011 00011110
UTF32 (big Endian)
00 00 1E 63
00000000 00000000 00011110 01100011
UTF32 (little Endian)
63 1E 00 00
01100011 00011110 00000000 00000000
HTML Entity
ṣ
URI Encoded
%E1%B9%A3

Description

The Unicode character U+1E63, known as LATIN SMALL LETTER S WITH DOT BELOW, serves a specific role in digital text as an alphabetical character from the Latin script. This particular character is used to represent the lowercase letter 's' with a dot below it, which can be found in many languages that utilize the Latin script. U+1E63 is primarily used for typographical purposes, such as in certain font styles or artistic representations of text, where the inclusion of diacritical marks like the dot below the letter add visual emphasis or distinction. In some cases, this character can also be utilized to depict a character from a non-Latin language that has been adapted to the Latin script. Overall, U+1E63 contributes to the diversity and expressiveness of digital text by offering variations in letterforms and diacritics.

How to type the symbol on Windows

Hold Alt and type 7779 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1E63. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1E63 to binary: 00011110 01100011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10111001 10100011