LEPCHA DIGIT TWO·U+1C42

Character Information

Code Point
U+1C42
HEX
1C42
Unicode Plane
Basic Multilingual Plane
Category
Decimal Digit Number

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B1 82
11100001 10110001 10000010
UTF16 (big Endian)
1C 42
00011100 01000010
UTF16 (little Endian)
42 1C
01000010 00011100
UTF32 (big Endian)
00 00 1C 42
00000000 00000000 00011100 01000010
UTF32 (little Endian)
42 1C 00 00
01000010 00011100 00000000 00000000
HTML Entity
᱂
URI Encoded
%E1%B1%82

Description

The character U+1C42, Lepcha Digit Two, is a numeral symbol from the Lepcha script, an abugida writing system used primarily in the Sikkim region of India and parts of Nepal by the Lepcha people. In digital text, it serves as a numerical representation, similar to its counterparts in other alphabets or scripts. The Lepcha Digit Two character plays a crucial role in preserving the cultural heritage and linguistic identity of the Lepcha community, which has been acknowledged by UNESCO under the program "Memory of the World." In the context of typography, U+1C42 is part of the Unicode Standard, which aims to standardize and promote the interchangeability of text across different platforms, devices, and applications. As an expert in typography and Unicode, it is essential to understand the significance of such characters in preserving linguistic diversity and ensuring accurate representation in digital communication.

How to type the symbol on Windows

Hold Alt and type 7234 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1C42. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1C42 to binary: 00011100 01000010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110001 10000010