LEPCHA LETTER TA·U+1C0A

Character Information

Code Point
U+1C0A
HEX
1C0A
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B0 8A
11100001 10110000 10001010
UTF16 (big Endian)
1C 0A
00011100 00001010
UTF16 (little Endian)
0A 1C
00001010 00011100
UTF32 (big Endian)
00 00 1C 0A
00000000 00000000 00011100 00001010
UTF32 (little Endian)
0A 1C 00 00
00001010 00011100 00000000 00000000
HTML Entity
ᰊ
URI Encoded
%E1%B0%8A

Description

U+1C0A, the Lepcha Letter Ta, is a unique character in the Unicode standard, representing a specific letter from the Lepcha script. The Lepcha language belongs to the Sino-Tibetan family of languages and is primarily spoken by the Lepcha people in Sikkim, India, and Nepal. As part of the digital text representation system, U+1C0A allows for the accurate encoding and display of traditional Lepcha literature in various electronic platforms, including websites, documents, and software applications. By enabling the preservation and promotion of indigenous languages, characters like U+1C0A contribute to cultural diversity and linguistic heritage on a global scale. The Lepcha script, which consists of 27 letters, was adapted from the Tibetan script and has been used since at least the 18th century.

How to type the symbol on Windows

Hold Alt and type 7178 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1C0A. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1C0A to binary: 00011100 00001010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110000 10001010