LEPCHA PUNCTUATION CER-WA·U+1C3D

Character Information

Code Point
U+1C3D
HEX
1C3D
Unicode Plane
Basic Multilingual Plane
Category
Other Punctuation

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B0 BD
11100001 10110000 10111101
UTF16 (big Endian)
1C 3D
00011100 00111101
UTF16 (little Endian)
3D 1C
00111101 00011100
UTF32 (big Endian)
00 00 1C 3D
00000000 00000000 00011100 00111101
UTF32 (little Endian)
3D 1C 00 00
00111101 00011100 00000000 00000000
HTML Entity
᰽
URI Encoded
%E1%B0%BD

Description

The Unicode character U+1C3D, Lepcha Punctuation Cer-wa, is an essential symbol in the Lepcha language, spoken primarily by the Lepcha people of Sikkim, India, and Nepal. This typographical element plays a critical role in digital text representation for the Lepcha script, facilitating accurate communication among speakers of this endangered language. The Cer-wa, like other punctuation marks, serves to clarify meaning and enhance readability by signaling pauses or breaks in speech, aiding readers in comprehending written texts more efficiently. Despite its niche application within the Lepcha script, U+1C3D demonstrates the value of Unicode's comprehensive character set, enabling digital preservation and accessibility of diverse linguistic heritage for generations to come.

How to type the symbol on Windows

Hold Alt and type 7229 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1C3D. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1C3D to binary: 00011100 00111101. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110000 10111101